@Harsh,
What type of discussion you would like to have?
e.g.
Study Methodology?
Resources?
GATE questions discussion?
Other?Also, lets try to make such discussions open on I n I instead of email so that it will be helpful for everybody who needs it.
What do you think?
@Kapil : First of all thanks of bringing this forum idea up.
@Harsh : Buddy I’d suggest you create a local group in your city/locality for GATE preparations.
Hey I just made my first post on this forum! This is Aditya, PM10 batch for CSIT at ACE Academy, Hyderabad
i would like all three to be included..
Study Methodology,
Resources,and
GATE questions [email protected] failed to get locate local people.:) too much net dependency 🙂
@kapil surely , open discussions are way better but haven’t found anyone interested yet ..
I did it finally 🙂
Do check Nikhils interview at https://www.inspirenignite.com/how-to-prepare-for-gate-nikhil-krishnan-air-4-gate-2011-part-1/Hope this give you all a direction..
Good Luck you all…
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You can use the formulae told by Ajay or you can think as follows:
3 user processes reqiuring 2 units of resource each. Meaning 3*2=6 resources will always suffice. But is it the minimum?? Lets try with 5..
If we have R=5, then 2 of the 3 process can hold their total requiremnt of 2 units, and 1 unit will be still remaining, which can be acquired by the 3rd process, now 3rd process will wait for another unit to get free. But since the other two processes have already got their 2 units, they can complete and release their resources, as soon as they complete, 4 resources will be freed and 3rd process can take any 1 of the 4 newly freed resources, and this way 3rd can also complete. So R=5 is alaso, but again, is it the minimum??
Letstry with 4… If each of the 3 process are holding 1 resource, their will be 1 recource left which any of the 3 can acquire and complete its execution and release its 2 units of resources, then the other two also complete… So 4 is the minimum R till now.
Lets try with R=3, IF each process is holding 1 resource then all the 3 units will be helded by some process and their will be no more units left, now each process will wait for 1 more resource to complete, which they will never get because of the hold and wait condition.. Thus 3 units of resource wont suffice here.
Thus 4 is the right answer.
Lol, If u r unable to understand this logic u can use the formulae as well.. i knew m bad at explaining things 😀
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Hello friends i am looking for people to prepare for GATE(CS)-2012 with Full dedication ….. i am finding it difficult to chose from books and locate them plus this is quit late to search for study material independently , therefore i wish if we people can unite , –> make schedules and stick to them while helping each other …
you can mail me : [email protected]
Best of luck everyone
Needing Support — Harsh Khatri