1. Harsh Khatri
        Member

        Hello friends i am looking for people to prepare for GATE(CS)-2012 with Full dedication ….. i am finding it difficult to chose from books and locate them plus this is quit late to search for study material independently , therefore i wish if we people can unite , –> make schedules andย  stick to them while helping each other …

        you can mail me : [email protected]

        Best of luck everyone

        Needingย  Support — Harsh Khatri

         

      1. Anonymous
        Inactive

        @Harsh,
        What type of discussion you would like to have?
        e.g.
        Study Methodology?
        Resources?
        GATE questions discussion?
        Other?

        Also, lets try to make such discussions open on I n I instead of email so that it will be helpful for everybody who needs it.

        What do you think?

      1. Aditya Joshi
        Member

        @Kapil : First of all thanks of bringing this forum idea up.

        @Harsh : Buddy I’d suggest you create a local group in your city/locality for GATE preparations.

        Hey I just made my first post on this forum! This is Aditya, PM10 batch for CSIT at ACE Academy, Hyderabad

      1. Inspire N Ignite
        Participant

        Welcome on board Aditya.

        Soon I am posting an interview with Nikhil Krishnan AIR 4 GATE 2011 ECE. He gave good idea about GATE study group. Hope that will help you all.
        Just pray that I dont become lazy ๐Ÿ™

      1. Harsh Khatri
        Member

        i would like all three to be included..
        Study Methodology,
        Resources,and
        GATE questions discussion.@Aditya failed to get locate local people.:) too much net dependency ๐Ÿ™‚

        @kapil
        surely , open discussions are way better but haven’t found anyone interested yet ..

      1. Inspire N Ignite
        Participant

        I did it finally ๐Ÿ™‚
        Do check Nikhils interview at https://www.inspirenignite.com/how-to-prepare-for-gate-nikhil-krishnan-air-4-gate-2011-part-1/

        Hope this give you all a direction..
        Good Luck you all…

      1. Mousumi Dhar
        Member

        Interested..
        Me too having no coaching or any good guide.. so dependent on net

      1. Gate Cse
        Member

        HI FRIENDS THOSE WHO ARE BELIEVING IN SELF STUDY PLZ CHECK THIS PAGE HERE U GET ALL KIND OF INFO ABOUT HOW TO PREPARE FOR GATE,WHAT ARE THE STRATEGY AND TRICKS , DIRECT FROM TOPPERS, CHECK EACH BLOG CAREFULLY
        HERE
        http://www.facebook.com/pages/GATE-Computer-Science/287782614585176

      1. Anusha Kurra
        Member

        free.the question is

        a computer has 6 tape drives with N process competing for them.. each process need 2 drives… then the max value for N to b deadlock free is??????
        plzz temme hw to find solution for this

      1. Lorin Ahmed
        Member

        I answered your question in the other thread anusha. ๐Ÿ™‚

      1. Anusha Kurra
        Member

        An operating system contains 3 user processes each requiring 2 units of resource R .The minimum number of units of R such that no deadlocks will ever arise is
        ans is given as 4 . i want the solution to solve this??????

      1. Lorin Ahmed
        Member

        You can use the formulae told by Ajay or you can think as follows:
        3 user processes reqiuring 2 units of resource each. Meaning 3*2=6 resources will always suffice. But is it the minimum?? Lets try with 5..
        If we have R=5, then 2 of the 3 process can hold their total requiremnt of 2 units, and 1 unit will be still remaining, which can be acquired by the 3rd process, now 3rd process will wait for another unit to get free. But since the other two processes have already got their 2 units, they can complete and release their resources, as soon as they complete, 4 resources will be freed and 3rd process can take any 1 of the 4 newly freed resources, and this way 3rd can also complete. So R=5 is alaso, but again, is it the minimum??
        Letstry with 4… If each of the 3 process are holding 1 resource, their will be 1 recource left which any of the 3 can acquire and complete its execution and release its 2 units of resources, then the other two also complete… So 4 is the minimum R till now.
        Lets try with R=3, IF each process is holding 1 resource then all the 3 units will be helded by some process and their will be no more units left, now each process will wait for 1 more resource to complete, which they will never get because of the hold and wait condition.. Thus 3 units of resource wont suffice here.
        Thus 4 is the right answer.
        Lol, If u r unable to understand this logic u can use the formulae as well.. i knew m bad at explaining things ๐Ÿ˜€

      1. Anusha Kurra
        Member

        if we apply the formulae in the other link

        then 3*2<3+R
        6<3+R
        3<R
        SO CHOICES ARE GIVEN AS FOLLOWS 4,5,6
        the above three options are satisfies so how can we knw 4 is the right answer

      1. Ajay Kumar
        Member

        Anusha : here they are asking minimum number of R so its obviously 4 only in ur choice in the list (4, 5,6)
        Any way its my own formula. it is not in any text book . u can apply and check and reply back

      1. Anusha Kurra
        Member

        @lorin ahmed
        i am unable to understand the logic u are trying to tell… can u plzz tell me in imple way..plzz

      1. Anusha Kurra
        Member

        @lorin ahmed

        i am unable to understand the logic u are trying to tellโ€ฆ can u plzz tell me in imple way..plzz

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