Applied Mechanics and Design Section Difficulties !!!!!!!

- 1. Chetankumar Mohane
    Member
    
    Ask any difficulties about Engineering Mechanics, TOM, SOM, DOM & Vibrations here.. Let help others & get helped from others also. What do you think?
    
    Nov 03, 2011 at 3:35 am
- 1. Ritesh Das
    Member
    
    how r u preparing for mechanics!!???…which book!!??…is this the first time u r writing gate??…
    
    Dec 13, 2011 at 9:29 am
- 1. Chetankumar Mohane
    Member
    
    This is my second attempt.
    Anyway I am not actually bothering too much about “Mechanics” bz I know if I prepare for SOM, TOM, Vibration & DOME well then the “Mechanics-Problems” will be automatically prepared!
    Remaining theory part concepts can be prepared from any standard book.
    Also you will see there are hardly 1 or 2 questions on the Mechanics Section!!!!
    
    Dec 14, 2011 at 3:24 am
- 1. Ganesh V Iyer
    Member
    
    There are two objects of mass ‘m’ connected over a frictionless pulley and are moving with velocity ‘v’.Inertia of pulley and friction is neglected.It is desired that the arrangement shd hv a max stopping time of ‘t’ from peak speed of ‘v’.What shd b the minimum power of the motor?(GATE 05 Mechanics question)
    Options:
    1)0.5*m*v*v
    2)0.5*m*v*v/t
    3)m*v*v/t
    4)2*m*v*v/t
    
    Dec 17, 2011 at 9:54 am
- 1. Ritesh Das
    Member
    
    @chetan….u r right…we dont have to give too much stress on mechanics..since problems asked in mechanics arent very difficult(most of the times)!!!
    
    Dec 17, 2011 at 12:11 pm
- 1. Ritesh Das
    Member
    
    and hey guys..have u joined any test series or coaching???…how ur analyzing ur performance from time to time??
    
    Dec 17, 2011 at 12:24 pm
- 1. Chetankumar Mohane
    Member
    
    @Ganesh, Frankly speaking I could not able to imagine the problem right!!! More explanation is needed 🙁
    whether they give any figure along with the question?
    You said this question is from GATE 05; please also state the stream (production, mech, civil) so that I can search this question there!!!
    Reply soon…
    
    Dec 18, 2011 at 11:46 am
- 1. Chetankumar Mohane
    Member
    
    @Ritesh, Exactly, thats what I wants to say, concentrate more on our core subjects 🙂
    
    Ritesh I haven’t joined any test series. Did you know any good organization??
    
    Dec 18, 2011 at 11:52 am
- 1. Ganesh V Iyer
    Member
    
    @chetan,sorry for not describing it right.Basically its best explained with the help of figure…Its from mechanics section of gate ’05(mech).Its like an elevator and counterbalance system.The two weights are freely suspended over a pulley by means of an inextensible string.One mass is moving up with velocity ‘v’ so naturally the other is going down with ‘v’.Sorry for replying late.
    
    Dec 19, 2011 at 3:23 pm
- 1. Ritesh Das
    Member
    
    @chetan..i joined targate test series…its very good!!!…but already six tests over…i doubt whether u can join now..!!!…how r u testing ur performance??…i attempted gate 2004 paper yesterday just like normal gate exam…scored only 55.25 out of 150…u can also do something like that..:)
    
    Dec 19, 2011 at 5:36 pm
- 1. Chetankumar Mohane
    Member
    
    @Ganesh, I got the question paper of GATE 2005 & read that question. Still I took much time to understand the question right. May be because of I am not aware of how exactly the elevator works. I always wondered that why that counterweight(CW) is there when we have electric motor in place. Then I googled it finally understands the use of CW is to save the energy.
    Now coming back to the question;
    Here, we can see the energy in the cage is in the form of K.E. which equals to, 0.5*m*v*v
    Also K.E. in counterweight(CW) is, 0.5*m*v*v
    Even the cage & CW are moving in opposite direction, they are pulling the chain in same direction (clockwise).
    So combining the two K.E.
    (0.5*m*v*v) + (0.5*m*v*v) = m*v*v
    Now the motor should have minimum energy which could be able to oppose this combined energy. In other words, the motor should do “WORK” to oppose the K.E. which is equals to, m*v*v.
    So, minimum work the motor must generate = m*v*v
    Now as we know, Power = Work done / time
    we can say,
    Minimum power the motor must have = (m*v*v)/t
    
    check out the answer.
    
    Dec 20, 2011 at 12:56 pm
- 1. Chetankumar Mohane
    Member
    
    @Ritesh, One of my friend also joined Targate test series. I think it is good organization; keep it up. If you find any interesting questions then you can post here on InI.
    
    I am also going to solve previous years papers in January. Right now I am studying. Still lots of study is left. But I must practice some papers. I wish I can start practicing as early as possible. 🙂
    
    Dec 20, 2011 at 1:15 pm
- 1. Ganesh V Iyer
    Member
    
    @chetan,i dont have the keys but i think your logic is correct.Thank you…….
    
    Dec 20, 2011 at 2:00 pm
- 1. Chetankumar Mohane
    Member
    
    For those who don’t know the question asked by Ganesh, Here it is:-
    Please right click the link and click on “open in new tab”
    
    http://i1233.photobucket.com/albums/ff399/mechaxe/Q41_GATE05.jpg
    
    Dec 21, 2011 at 5:19 am
- 1. Prithvi Yesudas
    Member
    
    my kind advice friends . gateforum targate test series is good but pls do not go for clasroom coaching . It is a waste of time and money . I am an ex gateforum student . this year i have taken coaching from DYNAMIC INSTITUTE , its solely for mech engg. and prof ramasubramaniam has given great results and his teachings are the best . if u attend his classes regularly and make use of his notes I would certainly assure you will Clear the exam with ease . you will get used to the gate pattern so well and you would do well in the interviews too .
    
    Jan 24, 2012 at 6:36 pm